Simple and best practice solution for (x^2)dyy(1x)dx=0 equation Check how easy it is, and learn it for the future Our solution is simple, and easy to understand, so don`t hesitate to use it as a solution of your homework If it's not what You are looking for type in the equation solver your own equation and let us solve itI calculate the answer to be y = tanC arctan(x) The original equation is separable, so you should get Integral of (1/(1 y^2))dy = Integral of (1/(1 x^2))dx which integrates to give arctan(y) = arctan(x) C where arctan(x) = tan^2/4/16 · But if I expand the bracket $(xy)^2$ before integrating I will get $$\varnothing_1=\int Mdx=\int (xy)^2dx=\int (x^22xyy^2)dx=\frac{x^3}{3}xy^2x^2y$$ Wich will lead to the solution $$\varnothing=\varnothing_1\varnothing_2=\frac{x^3}{3}xy^2x^2yy=Constant$$ What is the wrong step ?
Solve Y 2 2x 2y Dx 2x 3 Xy Dy 0 Mathematics Stack Exchange
